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NEC Article 220.61(B)(1)Worked ExampleElectrical

Household Electric Range Feeder Neutral Conductor Sizing

Calculate the maximum unbalance neutral feeder load for a household electric range using the 70% demand factor under NEC 220.61(B).

Direct Answer
5,600 W Neutral Demand (23.33 A Current Rating)

Calculated strictly in accordance with NEC Article 220.61(B)(1).

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Given Scenario Parameters

wattage8000
voltage240
continuousNon-continuous

Interactive Calculator (Pre-filled)

Adjust inputs to evaluate variations of this NEC code scenario.

Interactive Electric Load Calculator

Pre-loaded with NEC 220.51 & 424.3(B) parameters

Nameplate wattage of the heating unit or load

Line-to-line or line-to-neutral

NEC 424.3(B) mandates that fixed electric space heating equipment branch circuits must be sized at 125% of the total load current.

Calculated OutputLive Recalculation
Base Running Current33.33 A8000W ÷ 240V
Required Ampacity (125%)33.33 A33.33A × 1
Minimum Circuit Breaker:35 Ampere
Recommended Conductor (75°C Cu):8 AWG Copper
Overcurrent Protection Rule:NEC 240.4 & 424.3(B)
Adjust wattage or voltage on the left to recalculate continuous service loads instantly.

Step-by-Step Solution

Formal engineering derivation citing applicable National Electrical Code articles.

Governing Code Equation
Neutral Demand = Range Demand * 0.70
Citing NEC Article 220.61(B)(1)
1

Per NEC 220.61(B)(1), the feeder neutral demand for household electric ranges is assessed at 70% of the calculated demand from Table 220.55.

2

Base range demand from Table 220.55 = 8,000 Watts.

3

Calculate neutral demand: 8,000 W * 0.70 = 5,600 Watts.

4

Compute neutral current: 5,600 W / 240 V = 23.33 Amperes.

Conclusion: 5,600 W Neutral Demand (23.33 A Current Rating)
NEC Article 220.61(B)(1)