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NEC Article 220.55 & Table 220.55Worked ExampleElectrical

Household Electric Range Service Demand for 12 kW at 240V

Calculate minimum service demand for a 12 kW household electric range using NEC Table 220.55 Column C.

Direct Answer
8 kW Demand / 33.33 A Load (Minimum 40A Circuit Rating)

Calculated strictly in accordance with NEC Article 220.55 & Table 220.55.

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Given Scenario Parameters

wattage12000
voltage240
continuousNon-continuous

Interactive Calculator (Pre-filled)

Adjust inputs to evaluate variations of this NEC code scenario.

Interactive Electric Load Calculator

Pre-loaded with NEC 220.51 & 424.3(B) parameters

Nameplate wattage of the heating unit or load

Line-to-line or line-to-neutral

NEC 424.3(B) mandates that fixed electric space heating equipment branch circuits must be sized at 125% of the total load current.

Calculated OutputLive Recalculation
Base Running Current50 A12000W ÷ 240V
Required Ampacity (125%)50 A50A × 1
Minimum Circuit Breaker:50 Ampere
Recommended Conductor (75°C Cu):8 AWG Copper
Overcurrent Protection Rule:NEC 240.4 & 424.3(B)
Adjust wattage or voltage on the left to recalculate continuous service loads instantly.

Step-by-Step Solution

Formal engineering derivation citing applicable National Electrical Code articles.

Governing Code Equation
Demand = Table 220.55 Column C (8 kW max demand)
Citing NEC Article 220.55 & Table 220.55
1

Consult NEC Table 220.55 Column C for a single household range not exceeding 12 kW.

2

The maximum demand rating permitted is 8 kW (8,000 Watts).

3

Calculate minimum branch circuit current: 8,000 W / 240 V = 33.33 Amperes.

4

Apply minimum conductor rating per NEC 210.19(A)(3): Minimum 40 Ampere branch circuit required.

Conclusion: 8 kW Demand / 33.33 A Load (Minimum 40A Circuit Rating)
NEC Article 220.55 & Table 220.55